How many ways can an irs auditor select 5 of 12 tax returns for an audit?

  792

Step-by-step explanation:

The number of ways that k things can be chosen from a collection of n things is given by ...

  nCk = n!/(k!(n-k)!)

Here, we want the number of ways 5 items can be chosen from 12. That is ...

  12C5 = 12!/(5!·7!) = 12·11·10·9·8/(5·4·3·2·1) = 11·9·8

  12C5 = 792

There are 792 ways 5 returns can be chosen from 12.

the answer   is 200

step-by-step explanation:

this is a problem about poisson probabilities.   i don't know if you've

already studied poisson distributions, or if you have a place to look

to read more about the subject.  

here's how you can see a poisson distribution coming.   when there are

a lot of events that may happen at any time (or any place), and when

you're counting how many of them happen at a particular time (or a

particular place), and each event is independent of the others, then

the result is a poisson distribution.   this is roughly true for the

chocolate chips; one chip being in a cookie has only a small effect on

the probability that another chip will be in the cookie.

once you know you have a poisson distribution, you know a lot.   there

is only one parameter to a poisson distribution, so if you know the

mean, you know everything.   the form of the distribution is

  probability of n chips = {[e^(-x)]*(x^n)} / (n! )

answer: answer is c!

ok i got to organize the

3/15 and 12/55

3*

aha

3*4 equals 12 but not

a: no

b:

8/24 12/35

no

gautie

it's c

5/18 = 25/90

5*5=25

18*5 = 90

hope that you!

one more happy customer!

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step-by-step explanation: