If log(4)5 = a, log(5)6 = b, then prove that: log(3)2 = 2ab-1

⇒log4(5)×log5(6)=ab

⇒log4(6)=ab

⇒log(6) / log(4)=ab

⇒log(2×3) / log(4)=ab

⇒log(2)+log(3)l / log(4)=ab

⇒(1/2)+log(3) / 2log(2)=ab

⇒log(3) / 2log(2) =ab−(1/2)

⇒log2(3)=2(ab−1/2)=2ab−1

idk

step-by-step explanation:

i don't know

your answer is the frist one

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