What is the equation of a line that passes through (4,  3) and has a slope of 2? y=2x−11 y=2x−7 y=2x−1 y=2x−5

Step-by-step explanation:

The coefficient of the x term repesents the slope of the graph.

So we have y = 2x +- ( ).

We have to find our number term, so let's substitute x = 4 and y = 3.

(3) = 2(4) +- ( )

3 = 8 +- ( )

To make this right, the number term must be -5.

3 = 8 - 5

So the equation is y = 2x - 5.

Slope intercept formula is:

y = mx + b

m is the slope

b is the y-intercept

Since we know that the slope (m) is 2 we can start plugging that into the equation:

y = 2x + b

Now we must find b

To do that you must plug in the point the line goes through in the x and y of the equation.

(4, 3)

3 = 2(4) + b

3 = 8 + b

-5 = b

^^^Plug this into the equation

y = 2x - 5  

Hope this helped!

~Just a girl in love with Shawn Mendes

the correct answer to your question is a. 4^4

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27 + 13x + 15 = (x + 5)( =

step-by-step explanation:

27 + 13x + 15 = (x + 5)( = 27 + 13x + 15 = (x + 5)( = 27 + 13x + 15 = (x + 5)( =