The average (arithmetic mean) ages, in years, of the people in group a and group b are 41 and 36, respectively. the average age, in years, of the people in the two groups combined is 38. if there are no people in both group a and group b, what fraction of the people in the two groups combined are in group b?

3/5

Step-by-step explanation:

avg in A = 41

avg in B = 38

combined avg of A and B = 36

Let a = number of people in group A.

Let b = number of people in group B.

The total number of people = a + b.

The sum of all ages in group A is 41a.

The sum of all ages in group B is 36b.

The sum of all ages in the combined group A and B is 38(a + b).

41a + 36b = 38(a + b)

41a + 36b = 38a + 38b

3a = 2b

a/b = 2/3

a/b + 1 = 2/3 + 1

a/b + b/b = 2/3 + 3/3

(a + b)/b = 5/3

b/(a + b) = 3/5

80π/3 or about 83.775

step-by-step explanation:

since a cone is 1/3 of a cylinder, we need to find the base's area. since area = πr^2, we get 16π. then, multiplying this by 5, we get 80π. dividing by 3, since the cone's volume is 1/3 of that of a cylinder's, we get 80π/3.

hope this !