Adata set includes 106 body temperatures of healthy adult humans having a mean of 98.9 degrees f and a standard deviation of 0.62 degrees f. construct a 99 % confidence interval estimate of the mean body temperature of all healthy humans. what does the sample suggest about the use of 98.6 degrees f as the mean body temperature? what is the confidence interval estimate of the population mean? round to three decimal places as needed.

Step-by-step explanation:

Sample mean x bar = 98.9

Std dev s = 0.62

Sample size n = 106

Std error =

Since population std deviation not known we can use t critical value.

t critical for 99% with df = 105 is 1.98

Margin of error = ±1.98(0.0602) =±0.1192

Confidence interval for sample mean = (98.9±0.1192)

=(98.781, 99.019)

2) Sample mean confidence interval suggests that sample mean is different  from the population since 98.6 is not contained in the confidence interval.

3) Population interval confidence mean would be

98.6±0.1192

=(98.4808, 98.7192)

the solution is the point

step-by-step explanation:

we have

> equation a

> equation b

adds equation a and equation b

substitute the value of x in equation b to find the value of y

the solution is the point

sas (side angle side)

aa (angle angle)

sss(side side side)

sas find two sides with an angle in between

aa is finding two angles and the third will add up to 180

sss find all sides

step-by-step explanation: