Aminiature american eskimo dog has a mean weight of 15 pounds with a standard deviation of 2 pounds. assuming the weights of miniature eskimo dogs are normally distributed, what range of weights would 68% of the dogs have?
a.)approximately 13–17 pounds
b.)approximately 14–16 pounds
c.)approximately 11–19 pounds
d.)approximately 9–21 pounds

Approximately 13–17 pounds ⇒ answer A

Step-by-step explanation:

* Lets explain how to solve the problem

- The Empirical Rule states that almost all data lies within 3

standard deviations of the mean for a normal distribution.  

- 68% of the data falls within one standard deviation.  

- 95% of the data lies within two standard deviations.  

- 99.7% of the data lies Within three standard deviations  

- The empirical rule shows that

# 68% falls within the first standard deviation (µ ± σ)

# 95% within the first two standard deviations (µ ± 2σ)

# 99.7% within the first three standard deviations (µ ± 3σ).

* Lets solve the problem

- A miniature American Eskimo dog has a mean weight of 15 pounds

 with a standard deviation of 2 pounds

∴ µ = 15 and σ = 2

- The weights of miniature Eskimo dogs are normally distributed

- We need to know the range of weights would 68% of the

  dogs have

∵ 68% falls within the first standard deviation (µ ± σ)

∵ 15 - 2 = 13

∵ 15 + 2 = 17

∴ The range is approximately 13–17 pounds

its A

Step-by-step explanation:

your welcome!

there is no question content here, but you for the free points! : d

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°