Atriangle was dilated by a scale factor of 2. if cos a° = three fifths and segment fd measures 6 units, how long is segment de?
triangle def in which angle f is a right angle, angle d measures a degrees, and angle e measures b degrees
segment de = 3.6 units
segment de = 8 units
segment de = 10 units
segment de = 12.4 units

10 units

Step-by-step explanation:

The cos --> adjacent/ hypotenuse.

cos--> 3/5

FD is the adjacent which is 3

DF is the Hypotenuse which is 5

It then states it was dilated by a scale factor of 2, and ask for segment DE

You then take the Hypotenuse ( 5 ), and multiply it by 2 and it then equals 10.

Hope this helped sorry if i'm late. :)

Looking for brainliest answers if you can give pls, thx.

10 units

Step-by-step explanation:

Soh Cah Toa is a acronym used in trigonometry classes to help remember the right-triangle definitions for sine, cosine, and tangent.

We are really wanting to use the Cah part since we are given cos(a)=3/5.

So I know my adjacent side measurement to angle a is going to be of the form 3m and the hypotenuse measurement is going to 5m.

They later say angle D was the one that had measurement a degrees.  So I knew FD will be in the form 3k and ED would be in the form of 5k.

We are given FD is also 6.  

So 3k=6 units means k=2.  We were told we had a dilation of 2.  The triangle we dilated from originally had a measurement of 3 units there.

So we are looking for the measurement of ED which is 5k where k is 2. So ED has measurement 5(2)=10 units.

(0,,,0)

step-by-step explanation:

the table of x and y values is shown in the attached pic(part of question)

we have to decide according that graph

given points are (0, 0) (–1, 0), (2, 0)

when we graph these points on graph they show an increasing line as shown in the attached pic