A95% confidence interval estimate for the difference between the mean of all treated rats and the mean of all untreated rats was computed to be (1.08, 15.06). does this interval give us evidence to say that the means differs significantly at alpha = .05? why or why not?

Step-by-step explanation:

Given that a 95% confidence interval estimate for the difference between the mean of all treated rats and the mean of all untreated rats was computed to be (1.08, 15.06).

This gives mean = 8.07

This confidence interval says that we can be 95% confidence that mean difference would be atleast 1.08 and atmost 15.06

Since 0 is not contained in this interval we can say that there is evidence that the means differ significantly at alpha = 5%

0.16 or 16%

step-by-step explanation:

lets take a coin for example.

if you toss it twice, it has a 1/4 chance of landing on heads both times because 1/2 * 1/2 is 1/4.

with the cards, the chance of picking dog is 0.4. having two people pick one is like picking a card twice in a row. so 0.4 * 0.4 is 0.16, or 16%