Just before a referendum on a school budget, a local newspaper polls 402 voters to predict whether the budget will pass. suppose the budget has the support of 52% of the voters. what is the probability that the newspaper's sample will lead it to predict defeat?

21.21%

Step-by-step explanation:

Assume that proportion of support follows normal distribution.For resulting in defeat the proportion of support should less than 0.5.Given that the proportion of support is p= 0.52.

Sample size(n)= 402

We know that standard deviation is given as

Now by putting the values

σ=0.0249

Proportion of support follows normal distribution with mean is 0.52 and standard deviation is 0.0249

We know that

So

Z= -0.80

So P(Z<-.80) =0.2118 from standard table.

So the probability of news paper to predict defeat is 21.21%

true? is that what you're asking or do you mean something else?

after simplifying it i got: -36.25 as my answer. hope that !