How do you solve an equation like this: (2^ √2)^ √8

provide steps so i can learn how to do it.

Based on how I understand it.

Both radicals are exponents. I prefer to get the decimal value of each square root.

√2 = 1.414
√8 = 2.828

PEMDAS - Parenthesis, Exponents, Multiply, Divide, Add, Subtract

This is the order of operation. We need to solve first the numbers inside the parenthesis. I'll just use the decimal value.

(2^√2) ⇒ 2¹.⁴¹⁴ = 2.665
2.665^√8 ⇒ 2.665².⁸²⁸ = 15.990

(2^√2)^√8 = 15.99

Def is a scalene triangle