F(x)=|x-1|+2
i have to graph the function and don’t know how to get the y values.

Look at the attached image.

Step-by-step explanation:

To graph this, you need to find where the expression in between the absolute value sign is negative.

x-1 is zero when x=1 and negative when x > 1.

So the corner will be at x = 1

When x is greater than 1 you need to graph:

f(x) = -(x-1) + 2

f(x) = -x + 1 + 2

f(x) = -x + 3

When x is greater than 1 you need to graph:

f(x) = (x-1) + 2

f(x) = x - 1 + 2

f(x) = x - 1

I attached an image showing what the graph would look like.

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0

207/8 is the right