Factor.
-3(x - 1)^2 * (x - 2)^4 + (x - 1)(x - 2)^-3
show that:
sinθ cos^2θ - sinθ = -sin^3θ
solve.
x^-2 = (1/25)
solve the equation over the interval [0, 2pi].
2sinθ cosθ = 0
factor.
(x+1)(2x+3)^-(1/2) + (2x+3)^(1/2)
calculus review