[44-3] exercise designed to see cp as a self-contained
module:
use cp to the get the 1st part of conjunction; use the
conditional as a premise to get the 2nd part; & be
careful not to take the 2nd part of conjunction from cp
c: (h -> m) & ~f
1: ~h v ~f
2: ~m -> f
3: (~h v m) -> ~f

answer: sorry

step-by-step explanation: can you tell me pls how to find the rational of two integers

step-by-step explanation:

the answer is (-8,-5)

step-by-step explanation:

the endpoint to midpoint is half the length. the length is (-2,-1) so when you are at the midpoint just add it to it to find your answer -6+(-2)= -8 and -4+(-1)=-5 so (-8,-5)