Which of the following best completes the proof showing that δwxz ~ δxyz?
triangles wxz and xyz that share side xz with right angle xzw, wz equals 12, xz equals 6, and yz equals 3
since segment xz is perpendicular to segment wy, angles wzx and xzy are both right angles and congruent. the proportion shows the corresponding sides are proportional, so the triangles are similar by the sas similarity postulate.
6 over 12 equals 3 over 6
6 over 3 equals 6 over 12
6 over 6 equals 3 over 12
12 over 6 equals 3 over 6

g(x) = x² + 2

step-by-step explanation:

it is given that the graphs are the same shape.

the only difference is that the red graph is 2 units higher than the blue graph.

that is to say that the red graph is simply the blue graph that has been moved vertically by 2 units in the positive y direction.

hence

g(x) = f(x) + 2

or

g(x) = x² + 2

g = (2, 2)

step-by-step explanation:

given the ratio is 1 : 1 then f is the midpoint of eg

let the coordinates of g = (x, y)

using the midpoint formula

(0 + x) = 1 ( multiply both sides by 2 )

0 + x = 2 ⇒ x = 2

similarly

(4 + y) = 3 ( multiply both sides by 2 )

4 + y = 6 ( subtract 4 from both sides )

y = 2

coordinates of g = (2, 2)