Two fair six-sided dice are rolled. what is the probability that the sum of the numbers rolled is either 6 or 12? 136+136=236 536+112=29 536+136=16 16+136=736

Step-by-step explanation:

Two dices are rolled so total number of sample space =6×6=36

sample space

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (22) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

The event which has sum 6,  (1,5) (2,4) (3,3) (4,2) (5,1)

So the required probability

The event which has sum 12 , (6,6)

So the required probability =    

So the total probability =

the answer is:

the correct option:

b.

to solve the problem, we need to remember how to operate to simplify exponential expressions using the logarithms.

we are given the equation:

then, using placing logarith with base 7 on both sides of the equation, we have:

so, rounding the obtained result to two decimal places (nearest hundreth), we have:

hence, we have that the correct option:

b.

have a nice day!

15.36 per mile

but forgot to round

i am pretty sure