Anew restaurant with 138 seats is being planned. studies show that 59% of the customers demand a smoke-free area. how many seats should be in the non-smoking area in order to be very sure (mu plus 3 sigma) of having enough seating there?

Step-by-step explanation:

Given that a new restaurant with 138 seats is being planned. Studies show that 59% of the customers demand a smoke-free area.

Non smoke area = 100-59=41%

mu for non smoke area = 0.41

Std  deviation =

mu-3sigma =

mu+3 sigma =

Thus 28.43 to 53.54 percent should be in non smoke area

Or 39.2334 to 73.8852 seats

74 seats should be in the non-smoking area in order to be very sure (mu plus 3 sigma) of having enough seating there

an advantage of the standard deviation is that it increases as the dispersion of the data increases. e. the interquartile range is preferred when the data are not skewed or no have outliers. an advantage of the standard deviation is that it uses all the observations in its computation.

-1/2 +2

step-by-step explanation: