For a sample of eight bears, researchers measured the distances around the bears' chests and weighed the bears. minitab was used to find that the value of the linear correlation coefficient is requals0.952. using alphaequals0.05, determine if there is a linear correlation between chest size and weight. what proportion of the variation in weight can be explained by the linear relationship between weight and chest size?

Step-by-step explanation:

Given that for a sample of eight bears, researchers measured the distances around the bears' chests and weighed the bears.

r = linear correlation coeff = 0.952

H_0: r =0\\

H_1 :r\neq 0

(Two tailed test)

r difference = 0.952

n=8

Std error = \sqrt{\frac{1-r^2}{n-2} } =0.12496

Test statistic t = 0.952/0.12496 = 7.618

Alpha = 0.05

df = 6

p value = 0.000267

This implies H0 is rejected.

There exists a linear relation between the variables and r cannot be 0

0.952^2 = 0.906=90.6% of variation in weight can be explained by the linear relationship between weight and chest size

d. millimeters per hour.

step-by-step explanation:

we are given that,

carlo used a rain gauge to measure the amount of water his lawn is receiving from the sprinklers.

since, according to the options, we see that,

water cannot be measured by 'miles per hour', 'meters per second' and 'grams per seconds'.

we get that, the water can be measured by 'millimeters per hour'.

hence, the appropriate rate for describing the amount of water is 'millimeters per hour'.