An isosceles triangle has a base 10 units long. if the congruent side lengths have measures to the first decimal place, what is the shortest possible length of the sides?
question 7 options:
20.1
5.1
4.9
10.1

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

multiple all that

step-by-step explanation:

27×17

a orange at the grocery store idk what other product that could be

where are the graphs?

step-by-step explanation: