The random variable x has the following probability distribution: x f(x) 0 .25 1 .20 2 .15 3 .30 4 .10 a. is this probability distribution valid? explain and list the requirements for a valid probability distribution. b. calculate the expected value of x. c. calculate the variance of x. d. calculate the standard deviation of x.

Answer and Explanation:

Given : The random variable x has the following probability distribution.

To find :

a. Is this probability distribution valid? Explain and list the requirements for a valid probability distribution.

b. Calculate the expected value of x.

c. Calculate the variance of x.

d. Calculate the standard deviation of x.

Solution :

First we create the table as per requirements,

x      P(x)         xP(x)           x²            x²P(x)

0    0.25           0               0                0

1     0.20        0.20             1              0.20

2    0.15          0.3               4             0.6

3    0.30         0.9               9             2.7

4    0.10          0.4               16             1.6

   ∑P(x)=1     ∑xP(x)=1.8               ∑x²P(x)=5.1

a) To determine that table shows a probability distribution we add up all five probabilities if the sum is 1 then it is a valid distribution.

Yes it is a probability distribution.

b) The expected value of x is defined as

c) The variance of x is defined as

d) The standard deviation of x is  defined as

answer: 2x + 2 − 2 = 10 − 2; subtraction property of equality

step-by-step explanation:

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step-by-step explanation: