Prove: if λ is an eigenvalue of a, x is a corresponding eigenvector, and s is a scalar, then λ − s is an eigenvalue of a − si and x is a corresponding eigenvector.

the mistake in the pattern is that :

b. the decimal point was moved one too many place values each time

the correct pattern could be made by :

b. moving the decimal point to the right the same numbers of place values as the exponents

10000

step-by-step explanation: divide by 2,

1.3

step-by-step explanation:

3x2=6   9x+6

bring down the 6 on both sides

6+6=12

12= 9x

divide by 9

12/9 =

1.3 =x