Atotal of 3 cards are chosen at random, without replacing them, from a standard deck of 52 playing cards. what is the probability of choosing 3 king cards? 113⋅351⋅125=15525 113⋅113⋅113=313 452⋅352⋅252=417576 113⋅113⋅113=42197

Step-by-step explanation:

The total number of cards =52

The number of kings in the cards = 4

If repetition is not allowed , then the total number of ways of choosing 3 cards will be :-

The number of ways of choosing 3 kings will be :-

Now, the probability of choosing 3 king cards will be :-

Hence, the  probability of choosing 3 king cards  =

step-by-step explanation:

equation

you are asked to write the equation

  expression = 0

using the given expression. when you do that, you have

  2x^2-2x-12 = 0

factoring

you can see that each of the coefficients is even, so a factor of 2 can be removed immediately.

  2(x^2 -x -6) = 0

if you multiply the binomials (x+a)(x+b), you get

  (x +a)(x +b) = x^2 +(a+b)x +ab

this tells you the coefficient of x is the sum of two factors of the constant term. here, that means -1 is the sum of two factors of -6. we want to know those factors so we can factor the trinomial.

  -6 = -1×6 = -2×3 = -3×2 = -6×1

the factor pair that sums to -1 is {-3, 2}, so our factorization is

  2(x -3)(x +2) = 0

solutions

the solutions to this equation are the values of x that make the product zero. a product is zero only when only of the factors of the product is zero. here, that means

  x - 3 = 0

  x = 3 . . . add 3 to both sides of the equation

or

  x +2 = 0

  x = -2 . . . add -2 to both sides of the equation

the solutions to the equation are x=3 or x=-2. both of these values of x satisfy the equation—they make it be true.