Arandomly selected customer support wait time (from a normal distribution) is calculated to be 1.8 standard deviations above its mean. what is the probability that another randomly selected customer wait time from the distribution will be less than 1.8 standard deviations from the mean? round to four decimal places as needed.

0.9640

Step-by-step explanation:

Let be the mean wait time and be the standardr deviation.

Let x be the random variable that represents the wait time .

Given : A randomly selected customer support wait time (from a normal distribution) is calculated to be 1.8 standard deviations above its mean.

then ,

For z -score ,

By using standard normal distribution table , the probability that another randomly selected customer wait time from the distribution will be less than 1.8 standard deviations from the mean :-

shift 4 units up, and 1 unit left.

it will translate f(x) = 3^x to g(x) = 3^(x+1) + 4

hiking down a winding trail.

step-by-step explanation: