Sat math question
y is greater than or equal to (x-2)^2 + 4
y is less than or equal to -(x-2)^2 + 6
the ordered pair (a,5), where a is a constant, satisfies the system of inequalities above. what is the least possible value of a?

1

Step-by-step explanation:

Sometimes the easiest way to answer a question like this one is to graph it.

The point has to be closest to 1,5. It can also be 1,5

So the answer is a=1

1

Step-by-step explanation:

Let's plug the point into both inequalities.

We will solve both and see what values of they both have in common and then determine the least of that set.

Let's start with the first:

Subtract 4 on both sides:

We are looking for numbers whose squares are less than 1. Those numbers are between -1 and 1.

So this gives me:

Add 2 on all sides:

Now let's solve the other inequality:

Subtract 6 on both sides:

Multiply both sides by -1:

We are already solved this inequality above.

So the solution for is .

The smallest number of that set is 1.

i think the answer would be c

answer: i dont know but if you try hard you will get it right : )

step-by-step explanation: