Hurry i need (10 points)
solve sinø+1=cos2ø on the interval 0≤ø< 2π

Step-by-step explanation:

Step-by-step explanation:

We are going to have to use a double angle identity.

I'm going to write this in terms of sine since the left hand side of the equation is also in terms of sine.

So applying the Pythagorean Identity to the identity above gives you:

So the equation you have becomes:

Get one side to be 0.

I'm going to move everything on right side to left side.

When you move a term over from one side to another, you just need to change the sign in front it. so if is plus 1 on the right it is minus 1 on the left.

If it is minus then it is plus on the other side.

Combine the like terms (1-1):

Factor out the common factor on the left which is sin( )[/tex]

If you have a product is 0 then one of the factors must be zero (both could be 0 also).

or

I'm going to solve the first equation first.

when the y-coordinate on the unit circle is 0.

This happens at is the given interval you provided.

Let's solve the other equation:

Subtract 1 on both sides:

Divide both sides by 2:

So you are looking for when the y-coordinate is -1/2 on the unit circle.

This happens at

So the solution set is:

square root of 36/6 = 2.449489743

square root of 16/6 = 1.632993162

square root of 6 = 2.449489743

the answer is square root of 16/6 because the square root of 36/6 is the same answer as square root of 6 = 2.449489743