The polynomial p(x) has factors that include x, x+1 , and x-1. match each factor to the point on the graph of p(x) that it corresponds with.
1. x
2. x+1
3. x-1
answer choices:
a. (0,1)
b. (0,0)
c. (-1,0)
d. (0,-1)
e. (1,0)

1. x  => (0, 0) (Option B)

2. x+1  => (-1, 0) (Option C)

3. x-1  => (1, 0) (Option E)

Step-by-step explanation:

If some expression is the factor of any polynomial p(x), then this means p(x) = 0. This means that the y-coordinate for each factor is 0. This rules out the options A and D. Considering x, x+1, and x-1 as the factors of p(x), set all three expressions equal to zero. Therefore, x = 0, x + 1 = 0, and x - 1 = 0. Therefore, x = 0, x = -1 , and x = 1. This means that the factor x matches Option B, factor x + 1 matches Option C, and factor x - 1 matches Option E!!!

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3