Let set c = {even numbers between 1 and 99} and set d = {numbers between 1 and 150 that are evenly divisible by 10}.
what is c ∩ d?

C ∩ D = {10, 20, 30, 40, 50, 60, 70, 80, 90}

Step-by-step explanation:

Set C is basically,

C = { 2, 4, 6, 8, 10, 92, 94, 96, 98 }

And set D is,

D = {10, 20, 30, 40, 50, 60, 70, 80, 90, 100, 110, 120, 130, 140, 150}

We want to figure out C ∩ D, which means "C intersection D". Intersection means common. So we need to find the numbers that are common to both C and D.

First of all, set D is all even numbers, so we need to find which of the elements in Set D are part of Set C. Since set C's last element is 98, we exclude 100 and above from Set D, hence the element that are common to both sets are 10, 20, 30, 40, 50, 60, 70, 80, and 90.

So, C ∩ D = {10, 20, 30, 40, 50, 60, 70, 80, 90}

there are 25 people coming to the party

step-by-step explanation:

the text says that there will be 22 children at this party, 1 teacher, and 2 parents. so if you add them all together (22+1+2) it will equal 25. (=25)