Perform the indicated operation. 6a/8b÷10c/12d

=9ad/10bc

Step-by-step explanation:

6a/8b÷10c/12d

3a/4b÷5c/6d

3a/4b×6d/5c

18ad/20bc

=9ad/10bc

angle q= 92 degree

step-by-step explanation:

the solution is in the picture

when a quadrilateral is inscribed in a circle, the opposite angles are supplement to each other. in other words, the sum of the 2 angle is 180 degree

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐