Mathematics, 02.08.2019 06:10 ParkBecca

Two planes leave the same point at 8 am. plane 1 head east at 600 mph and plane 2 head west at 450 mph
question 1) how long will they be 1400 miles apart? ?
question 2) at what time will they be 1400 miles apart? ?
question 3) how far has each plane traveled

Answers: 3

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Answer from: familygrahambusiness

(1). Planes will be 1400 miles apart after $1\frac{1}{3}$ hours.

(2). Both the planes will be 1400 miles apart at 9:20 A.M.

(3). Plane 1 and plane 2 will travel 800 miles and 600 miles respectively.

Speed, distance and times of an object,

Speed of an object is given by,

$\text{Speed}=\frac{\text{Distance}}{\text{Time}}$

(1). Given in the question,

Two planes heading in opposite directions.Speed of a plane heading East = 600 mphSpeed of the second plane heading West = 450 mph

Let both the planes travel for 't' hours,

Distance traveled by 1st plane = Speed × Time

= 600 × t

Distance traveled by 2nd plane = 450 × t

Distance between these planes = 1400 miles

Therefore, equation for the total distance traveled by them will be,

600t + 450t = 1400

Simplify the equation for the value of 't'

1050t = 1400

t = $1\frac{1}{3}$ hours

Therefore, both the planes will be 1400 miles apart after $1\frac{1}{3}$ hours.

(2). Both the planes left at 8 A.M.

After traveling for $1\frac{1}{3}$ hours, time will be → 8 + $(1+\frac{1}{3}\times 60)$ = 9.20 A.M.

Therefore, at 9.20 AM both the plane will be 1400 miles apart.

(3). Distance traveled = Speed × Time

Distance traveled by plane 1 = $600\times \frac{4}{3}$

= 800 miles

Distance traveled by plane 2 = $450\times \frac{4}{3}$

= 600 miles

Therefore, distances traveled by the planes 1 and plane 2 will be

800 miles and 600 miles respectively.

Learn more about the speed, distance and time here,

link

Answer from: MadisonMayberry9650

Question 1: They will be 1400 miles apart after 4/3 hours (1 hr and 20 min)

Question 2: The time will be 9:20 AM.

Question 3: Plane 1 has traveled 800 miles, Plane 2 has traveled 600 miles

Step-by-step explanation:

* Lets explain how to solve the problem

- Two planes leave the same point at 8 AM

- Plane 1 head east at 600 mph

- Plane 2 head west at 450 mph

# Question 1:

- After t hours the distance between them will be 1400 miles

∵ The speed of plane 1 is 600 mph

∴ The distance it has moved in t hours = 600 × t = 600t

∵ The speed of plane 2 is 450 mph

∴ The distance it has moved in t hours = 450 × t = 450t

∵ Plane 1 head east and and plane 2 head west

- East and west are on the same line but in opposite direction

∵ The distance between them after t hours is 1400 miles

∴ Distance of plane 1 + distance of plane 2 = 1400

∴ 600t + 450t = 1400

∴ 1050t = 1400 ⇒ divide both sides by 1050

∴ t = 4/3

∴ They will be 1400 miles apart after 4/3 hours (1 hr and 20 min)

# Question 2:

∵ The two planes leave at 8 AM.

∵ They move for 1 hour and 20 minutes

∴ The time will be 9:20 AM.

# Question 3:

∵ The speed of plane 1 is 600 mph

∵ It has traveled for 4/3 hours

∴ Its distance = 600 × 4/3 = 800 miles

* Plane 1 has traveled 800 miles

∵ The speed of plane 2 is 450 mph

∵ It has traveled for 4/3 hours

∴ Its distance = 450 × 4/3 = 600 miles

* Plane 2 has traveled 600 miles

Answer from: Quest

25 is obviously the correct answer

Answer from: Quest

Th is not an attachment

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