If h(x) = 3x − 1 and j(x) = −2x, solve h[j(2)] and select the correct answer below.
−11
11
−13
13

Option 3rd is correct.

the value of h[j(2)]  is, -13

Step-by-step explanation:

Given the functions:

We have to find the value of  h[j(2)]

Replace x from -2x in h(x) we have;

⇒

Substitute the value of x = 2 we get;

Therefore, the value of h[j(2)]  is, -13

v = 1/3 a^2h

step-by-step explanation:

the volume is 1/3 a^2h.

x:       y:  

-1         4

0         4

1         6

2         18

3         20