Suppose you just received a shipment of fourteen televisions. three of the televisions are defective. if two televisions are randomly selected, compute the probability that both televisions work. what is the probability at least one of the two televisions does not work?

Answer with explanation:

Given : Total number of televisions received = 14

Number of defective televisions = 3

Probability of defective televisions :

Now, If two televisions are randomly selected,  then the probability that both televisions work.

Hence, the probability that both televisions work is 0.5289 .

The probability at least one of the two televisions does not work will be :-

Hence, the probability at least one of the two televisions does not work is 0.4711.

3< x< 5

step-by-step explanation:

|x - 4| < 1

there are two solutions, one positive and one negative.   remember to flip the inequality when taking the negative solution

x-4 < 1       x-4 > -1

add 4 to each side

x-4+4 < 1+4       x-4+4 > -1+4

x< 5                 x> 3

3< x< 5