One diagonal of a rhombus has endpoints (-10, 1) and (2, 9). what are the endpoints of the other diagonal?

The end points of other diagonal are  (-2, 2) and (-6, 8)

Step-by-step explanation:

The given end points of a diagonal are (-10, 1) and (2, 9)

The given diagonal has mid point:

((-10, 1) +(2, 9))/2

= (-4, 5)

Proposed diagonal must have similar mid points.

The given diagonal has a slope:

= (9-1)/(2-(-10))

= 8/2+10

= 8/12

= 2/3

Proposed diagonal must have a slope that is perpendicular: -3/2

Thus the end points of other diagonal are  (-2, 2) and (-6, 8)

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3

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step-by-step explanation:

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