In △abc, m∠a=57°, m∠b=37°, and a=11. find c to the nearest tenth.

c = 13.1

Step-by-step explanation:

* Lets explain how to solve the problem

- In Δ ABC

# ∠A is opposite to side a

# ∠B is opposite to side b

# ∠C is opposite to side c

- The sine rule is:

#

* Lets solve the problem

- In Δ ABC

∵ m∠A = 57°

∵ m∠B = 37°

∵ The sum of the measures of the interior angles of a triangle is 180°

∴ m∠A + m∠B + m∠C = 180°

∴ 57° + 37° + m∠C = 180°

∴ 94° + m∠C = 180° ⇒ subtract 94° from both sides

∴ m∠C = 86°

- Lets use the sine rule to find c

∵ a = 11 and m∠A = 57°

∵ m∠C = 86°

∵

- By using cross multiplication

∴ c sin(57) = 11 sin(86) ⇒ divide both sides by sin(57)

∴

* c = 13.1

dalila is incorrect. the whisker on the left is very long, going all the way out to 5. the whisker goes from 5 to 30, so it has a spread of 25. the rest of the box plot values are closer together, so 5 is an outlier