Solve the homogeneous linear odes with constant coefficients: y" - 6y' + 8y = 0. m^2 - 6m + 8 = 0 (m - 2)(m - 4) m_1 = 2 m_2 = 4 y = c_1 e^2x + c_2 x e^4x y" - 6y' + 9y = 0. m^2 - 6m + 9 = 0 (m - 3)^2 = 0 m_1 = m_2 = 3 y = c_1 e^3x + c_2 x e^3x y" - 6y' 10y = 0. y"' + 3y" + 3y' + y = 0 y_1 = x^4 is a solution to the ode x^2 y" - 7xy' + 16y = 0, use reduction of order to find another independent solution.

proofs involving isosceles triangles often require special consideration because an isosceles triangle has several distinct properties that do not apply to normal triangles.(more about triangle types) therefore, when you are trying to prove that two triangles are congruent, and one or both triangles, are isosceles you have a few theorems that you can use to make your life easier.

step-by-step explanation:

an isosceles triangle has two congruent sides and two congruent angles. the congruent angles are called the base angles and the other angle is known as the vertex angle. ∠bac and ∠bca are the base angles of the triangle picture on the left. the vertex angle is ∠abc

a

step-by-step explanation:

strong negative correlation

ca = ec

cpctc makes it so that corresponding parts of the triangle you proved to be equal are equal, the other options aren't part of the part of the triangles you proved to be equal.

x= cost per bracelet

number of bracelets * x + shipping charge = total cost

so

9x+9=72