Use variation of parameters to find a particular solution of y" - y = 1/e^x + e^-x.

Step-by-step explanation:

Given:

First we will find homogeneous solution:

Let be the solution of equation

we get,

. Since , we will solve equation:

We get homogeneous solution as

For particular solution:

On comparing with , we get

Particular solution is of form .

Here,

Let

we get,

So, we get particular solution as:

Therefore, solution is

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.

22.83 repeating

step-by-step explanation:

137 ÷ 6 is 22.8333333 therefore we understand that 3 is repeating.

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