What is the distance between points (3,3) and (43/26, 71/26)

the desired distance is 49/26 units

Step-by-step explanation:

The horizontal distance is 43/26 - 3; the vertical distance is 71/26 - 3.

Rewriting these with denominator 26 yields horiz. dist. 35/26 and vert. dist. -7/26.

Applying the Pythagorean Theorem to find the distance between the two points, we get:

d^2 = (35/26)^2 + (-7/26)^2, or

d^2 = 49/26

Then the desired distance is 49/26 units.

the least value out of the data shown is 5, maybe if you post a picture with it i could a little more.

step-by-step explanation: