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Mathematics, 30.07.2019 01:20 cloudyyt78

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okay, now we can do the same thing with the grapes, just to give you that extra practice with quadratic functions. the starting price of grapes per m² is $8.00, at which you can sell 60 m² worth. for every $3.00 increase in price, you sell 3 m² less. so use the same method you just used to find the price of grapes per m² of area in order to maximize revenue.
equation:
r=
number of price increases: x=
price of grape per m^2=

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okay, now we can do the same thing with the grapes, just to give you that extra practic...
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