Suppose a small metal object, initially at a temperature of 50 degrees, is immersed in a room which is held at the constant temperature of 80 degrees. it takes 1 minutes for the temperature of the object to reach 65 degrees. 1. calculate the heat transfer coefficient r, i. e. the constant of proportionality in the differential equation that describes newton's law of cooling. 2. suppose now that the room temperature begins to vary; i. e. troom(t) = 70 + sin(0.1 t) . use newton's law of cooling and the heat transfer coefficient you calculated in the previous step to compute the temperature of the object as a function of time. suppose that t(0) = 65.

the correct answer is semicircle

step-by-step explanation:

the answer is semicircle because the shorter arc joining two points on the circumference of a circle is known as the minor arc, the larger arc is called the major arc, and a semicircle is a half circle, formed by cutting a whole circle along a diameter line.

hope i .

center (1,3) with radius 6

step-by-step explanation:

we must complete the square to find the center and radius of the circle.

first make sure the x and y squared terms have 1 as their coefficients. we also make sure x and y terms together.

we now create space between the x and y terms with parenthesis.

we complete the square by taking the middle terms -2x and the -6y - divide each and square them.

we add the squares to both sides.

simplify.

and write the quadratics in factored form.

the center is (h,k) or (1,3). the radius is the square root of 36 which is 6.

option a is correct.

only one solution to the system of equations

step-by-step explanation:

if the graph of the equations do not intersects(i.,e if they are parallel) then, there are no solutions that are true for both the equations.

if the graph of the equations intersects, then there is one solution and that is true for both the equations.

since, in the given figure:

the two lines intersect each other

⇒there is only one solution which satisfy both the lines of an equations.

therefore, there is only one solution to the system of equation