Two submersibles, one red and one blue, started rising toward the surface at the same time. they each rose at a constant speed.
the red submersible started rising from an altitude of 80 meters below the surface. after 30 seconds, it was 60 meters below the surface.
the following equation gives the altitude (in meters relative to the surface) of the blue submersible as a function of time (in seconds).
a=−90+0.6t
which submersible started rising from a higher altitude?
which submersible rose faster?

what do you need me to answer?

step-by-step explanation:

its d. the first coordintaes are 10,32

step-by-step explanation:

question 1 is 8, question 2 is 9, question 3 is 24

step-by-step explanation:

now, the numbers they give you at the top are the key. from there, you just have to plug and chug! let's try 1, 2, and 3!

key: a=3, b=5, c=6

1. a+5

remember, a=3, so we plug that in to get 3+5=8

2. 15-c

c=6, so we plug that in to get 15-6=9

3. 4b

b=6, so we plug it in to get 4*6=24

time to try the rest on your own! if you put the answers below in a comment, i'll check them for you!