Which are real zeroes of this function? x3 + 2x2 – 9x – 18
a. 1, 2, 3
b. 3, -3, 2
c. 2, 3, -6
d. 1, -1, 18
e. -2, 3, -3

The answer is:

E. -2, 3, -3

To find the zeroes of the function, we just need to evaluate the given values and check if the function/expression tends to 0.

We are given the function

Now, to find the zeroes, we need to substitute the values, so, substituting the values of the option E, we have:

First value, -2:

Second value, 3:

Third value, -3:

Hence, we have that evaluating the values of the option E, the function tends to 0.

So, the correct option is: E. -2, 3, -3

Have a nice day!

c 1 hour

step-by-step explanation:

m = 2e

m = 2 so 2 = 2e

1 = e