City a and city b had two different temperatures on a particular day four times the temperature of city a was 8c more than 3 times the temperature of city b the temperature of city a minus twice the temperature of city b was -3c what was the temperature of city a and city b on that day

temperature of city a=5

temperature of city b=4

Step-by-step explanation:

Given:

Let temperature of city A= a

temperature of city B=b

As given:

4a=8+3b

a-2b=-3

rearranging 2nd equation we get:

a=-3+2b

substituting above in 1st equation we get:

4(-3+2b)-3b=8

8b - 12 = 3b + 8

8b-3b=12+8

5b = 20

b = 4

Now substituting b=4 in 4a = 8 + 3b , we get

4a = 8 + 3b

4a = 8 + 3(4)

4a = 8 + 12

4a = 20

a = 20/4

a = 5

temperature of city a and city b on that day is 5C and 4C respectively!

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )