The perimeter of a triangle with two equal sides is 50 cm. if its base were lengthened by 3 cm and each leg were shortened by 4 cm, all three sides would be equal. find the length of the base of the original triangle.

Base of the original triangle is 12 cm.

Step-by-step explanation:

Let base of triangle be x  

two equal legs  of triangles by y

therefore perimeter of triangle

                       x+y+y = 50 or x+2y =50

according to the question

 if base is x+3 and leg is y-4

then both are equal

   that is x+3 = y-4

            y-x = 7 or y =x+7

   x+2y =50

   x+2(x+7) = 50

    x+2x +14 =50

     3x +14 =50

     3x = 50 -14

      3x = 36

      x = 12

therefore base of the original  triangle is 12 cm                    

here you hope this .

step-by-step explanation:

hypotenuse = √(15² + 8²)

=  √(225 +64)

=  √(289) = 17

sin(x) = cos(y) = 8/17

they are identical so long as you are doing the sine of one angle and the cosine of the only other angle that isn't the right angle.

see attached

step-by-step explanation:

given the function as;

write the equation replacing f(x) with y

form   and fill a table containing values of y with corresponding values of x

you can take a range for   values of x as -3≤x≤3

solving for x=-3

for x=-2

repeat the same procedure to get the values of y for the remaining ,x=-1 to x=3

plot the values of y against values   of x and obtain the following graph