(b−7)(b+2)=b^2−5b−14
khalil says that b^2−5b−14 is a factor of (b-7)
Mathematics, 26.07.2019 00:10 Azaleaz
Math multiple !
(b−7)(b+2)=b^2−5b−14
khalil says that b^2−5b−14 is a factor of (b-7)
ramata says that b^2-5b-14 is divisible by b-7
who is correct?
a khalil
b ramata
c both
d neither
Answers: 3
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Math multiple !
(b−7)(b+2)=b^2−5b−14
khalil says that b^2−5b−14 is a factor of (b-7)
(b−7)(b+2)=b^2−5b−14
khalil says that b^2−5b−14 is a factor of (b-7)
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