Find the directional derivative of f(x, y,z)=2z2x+y3f(x, y,z)=2z2x+y3 at the point (−1,4,3)(−1,4,3) in the direction of the vector 15–√i+25–√j15i+25j. (use symbolic notation and fractions where needed.)

has gradient

which at the point (-1, 4, 3) has a value of

I'm not sure what the given direction vector is supposed to be, but my best guess is that it's intended to say , in which case we have

Then the derivative of at (-1, 4, 3) in the direction of is

true

step-by-step explanation:

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