Ashipping company must design a closed rectangular shipping crate with a square base. the volume is 3072ft3. the material for the top and sides costs $4 per square foot and the material for the bottom costs $2 per square foot. find the dimensions of the crate that will minimize the total cost of material.

The dimensions are: length = 16 feet, width = 16 feet and height = 12 feet

or Dimensions are  16 ft *16 ft *12 ft

Step-by-step explanation:

Given:

Volume of rectangular with square base is 3072 cubic feet.

Let "x" be the side of the square and "h" be the height of the rectangular.

Volume of the rectangular (V) = area of the base * height

Now plug in the given value V = 3072

3072 = -------------------(1)

Let's find the area of the top.

Which is the square. The area of the top =

The area of the bottom is the same =

The area of the side = x*h

There are 4 sides, therefore, the areas of the 4 sides = 4xh

Now let's find the total cost.

Given: The material for the top and sides costs $4 per square foot and the material for the bottom costs $2 per square foot.

Total cost (T)=

Now let's find h from the equation (1)

h =

Now plug in h = in Total cost (T), we get

T =

Simplifying the above, we get

T =

To find the minimize the total cost, we need to find the derivative of T with respect to x.

T'(x) = 12x -

Now set the derivative equal to zero and find the value of x.

12x - = 0

Dividing both sides by 12, we get

Taking the cube root on both sides, we get

x = 16

Therefore, the length and the width of the base is 16

Now we have to find height.

height =  

Now plug in x = 16 in the above height, we get

height =

Therefore, the height of the rectangular shipping crate is 12 feet.

So, the dimensions of the crate that will minimize the total cost of material are length = 16 feet, width = 16 feet and height = 12 feet.

9 sandwiches per hour

step-by-step explanation:

when we have a rate, we want a 1 in the denominator

27/3 = 9

27 sandwiches/ 3 hours = 9 sandwiches/hour