Amom walks into her child's room and finds clothes all over the floor. 20% of the
clothes are clean. she randomly picks up 5 articles of clothing.

1 clean cloth

Step-by-step explanation:

Assuming that the problem is asking the number of clean clothes she picks up when she picked 5 articles.

here we are given that , there are 20% clothes in the room. Hence out of 5 clothes she picks up, the total number of clean clothes will be 20% of 5

20% of 5 will be 0.20 x 5 = 1

Hence , there will be only  clothe that might be clean among the clothes she picks .

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

d i think

step-by-step explanation: