The owner of a 4000-gal oil truck loads the truck with gasoline and keroseno. the profit on each gallon of gasoline is 16e and on each gallon of kerosene it is 12¢. how many gallons of each fuel did the owner load it
the profit was $620?
there
gallons of gasoline and
of kerosene.

There were 35 gallons of gasoline and 500 gallons of kerosene.

Step-by-step explanation:

Step 1: Write data for equation 1

Let gallons of kerosene be x

Let gallons of gasoline be y

Total capacity of truck is 4000

Step 2: Form equation 1

x + y = 4000

Step 3: Write data for equation 2

Profit of total gallons of kerosene is 0.12x

Profit of total gallons of gasoline is 16y

Total profit is $620

Step 4: Form equation 2

0.12x + 16y = 620

Step 5: Find x in terms of y from equation 1

x + y = 4000

x = 4000 - y

Step 6: Substitute value of x in equation 2

0.12x + 16y = 620

0.12 (4000 - y) + 16y = 620

480 - 12y + 16y = 620

4y = 620 - 480

y = 140/4

y = 35

Step 7: Substitute value of y in equation 1 to find x

0.12x + 16y = 620

0.12x + 16 ( 35 ) = 620

0.12x = 60

x = 500

There were 35 gallons of gasoline and 500 gallons of kerosene.

!!

8121 because

130,000 divided by 16 is 8121

18

step-by-step explanation:

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