Out of 100 people at a tennis match, 66% were rooting for the local champion. if two people were chosen at random from the crowd, what is the probability that at least one of them was not rooting for the champion?
question 16 options:
22.7%
56.7%
59.2%
43.3%

Approximately 56.7%.

Step-by-step explanation:

Choose two people at random from the crowd and there will be two cases:

There's no third possible outcome. In other words, the two cases are mutually exclusive. Either the first or the second event is expected to happen. The sum of their probabilities shall equal to 1.

66 out of that 100 were rooting for the champion. The probability that both were rooting for the champion will be easier to find. The probability that the first person is rooting for the champion is equal to .

After that first person was chosen from the crowd, the 65 out of the remaining 99 person in the crowd were chanting. The probability that the second person is rooting as well will equal to .

Both event shall take place. The probability that both were rooting for the champion will equal to

.

The probability that one or zero out of the two persons were rooting will equal to

.

by definition, an arc subtended by a central angle of some given measure has the same measure. so .

rick has $1400 and sally has $1500

step-by-step explanation:

to find amount of money rick has after 10 years :

principal = $1000 , time = 10 years , rate = 4% annually

to find amount of money sally has after 10 years :

her friend gives to pay her $50 per year, therefore money she has after 10 years = 50 × 10 = $500

also, sally gets $1000 after 10 years,

therefore, total amount of money sally has after 10 years = 500 + 1000 = $1500

so, after 10 years : rick has $1400 and sally has $1500