Now there is a door whose height is more than its width by 6 chi 8 cun. the distance between the [opposite] corners is 1 zhang. find the height and width of the door. note: 1 zhang = 10 chi = 100 cun. give your answers inunits of chi and cun.

Step-by-step explanation:

The factor-of-ten relationship between the different units means we can combine the numbers in decimal fashion. If 1 unit is 1 zhang, then 1 chi is 0.1 zhang and 1 cun is 0.01 zhang. Hence 6 chi 8 cun is 0.68 zhang.

Let x and y represent the width and height, respectively. In terms of zhang, we have ...

  y - x = 0.68

  x^2 +y^2 = 1^2

Substituting y = 0.68 +x into the second equation gives ...

  x^2 + (x +0.68)^2 = 1

  2x^2 +1.36x - 0.5376 = 0 . . . . . eliminate parentheses, subtract 1

Using the quadratic formula, we have ...

  x = (-1.36 ±√(1.36^2 -4(2)(-0.5376)))/(2·2) = (-1.36 ±√6.1504)/4

  x = 0.28 . . . . . the negative root is of no interest

  y = 0.28 +0.68 = 0.96

In units of chi and cun, the dimensions are ...

  height: 9 chi 6 cun

  width: 2 chi 8 cun

Height: 9 chi 6 cun

Width: 2 chi 8 cun

Step-by-step explanation:

Now there is a door whose height is more than its width by 6 chi 8 cun. The distance between the [opposite] corners is 1 zhang. The height of the door is  9 chi 6 cun  and the width of the door is 2 chi 8 cun.

1 zhang = 10 chi = 100 cun

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option

b

step-by-step explanation: