If z is a standard normal variable, find the probability.
p(–0.73 < z < 2.27)
0.2211
0.4884
1.54
0.7557

The probability that P(–0.73 < z < 2.27) is 0.7557.

The z score is used to determine by how many standard deviations, the raw score is above or below the mean. The z score is given by:

From the normal distribution table, P(-0.73 ≤ z ≤ 2.27) = P(z < 2.27) - P(z<-0.73) = 0.9884 - 0.2327 = 0.7557

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0.7557

Step-by-step explanation:

In this question use the Table of Standard Normal Probabilities for Negative z-scores and the Table of Standard Normal Probabilities for Positive z-scores

Where z=2.27 NORMDIST(2.27)=0.9884 (read from table for positive z-scores)

Where z=-0.73 NORMDIST(-0.73)=0.2327 (read from table for negative z-scores)

You know P(-0.73<z<2.27)= 0.9884-0.2327=0.7557

6mm^3 or .6cm^3

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6     6   6

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