3x^2-2x-5
subject is factoring quadratic trinomials when a doesn’t =1

(x + 1)(3x - 5)

Step-by-step explanation:

Given

3x² - 2x - 5

To factor the quadratic

Consider the factors of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term

product = 3 × - 5 = - 15 and sum = - 2

The required factors are - 5 and + 3

Use these factors to split the x- term

3x² + 3x - 5x - 5 ( factor the first/second and third/fourth terms )

= 3x(x + 1) - 5(x + 1) ← factor out (x + 1) from each term

= (x + 1)(3x - 5) ← in factored form

36/60

36/2=18

60/2=30

18/30

18/3=6

30/3=10

6/10

6/2=3

10/2=5

your final answer would be 3/5 of an

hope this !

y-y1=4(x-x1)

step-by-step explanation:

this is point-slope form since you only have 4 as the slope it goes in place of m

hope this : )